What is expand e^{4t-36}*u(t-9) ?

The solution to expand e^{4t-36}*u(t-9) is e^{4t-36}tu-9e^{4t-36}u

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^{4t-36}*u(t-9)

expand

e^{4 t - 36} \cdot u (t - 9)

e^{4 t - 36} t u - 9 e^{4 t - 36} u

Solution steps

e^{4 t - 36} u (t - 9)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{4 t - 36} u, b = t, c = 9

= e^{4 t - 36} u t - e^{4 t - 36} u \cdot 9

= e^{4 t - 36} t u - 9 e^{4 t - 36} u

\frac{4 t}{( t ^{2} + 1 ) ^{2}}

(1 - e^{- a}) (1 - e^{- a - bk}) (1 - e^{- a - 3 bk})

(- 7 x - 3 y = - 31) \cdot (- 4)

\frac{5 x ^{2} - 4 x + 4}{( x ^{2} + 1 ) ( x - 2 ) ( x + 2 )}

\frac{( 2 + 2 cos ( θ ) ) ^{2}}{2}

What is expand e^{4t-36}*u(t-9) ?
The solution to expand e^{4t-36}*u(t-9) is e^{4t-36}tu-9e^{4t-36}u