What is expand (x^2+1)y''(x)+4xy'(x)+2y ?

The solution to expand (x^2+1)y''(x)+4xy'(x)+2y is x^2y''(x)+y''(x)+4xy'(x)+2y

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expand (x^2+1)y''(x)+4xy'(x)+2y

expand

(x^{2} + 1) y^{''} (x) + 4 x y^{'} (x) + 2 y

x^{2} y'' (x) + y'' (x) + 4 x y' (x) + 2 y

Solution steps

(x^{2} + 1) y^{''} (x) + 4 x y^{'} (x) + 2 y

Expand

y^{''} (x) (x^{2} + 1) : x^{2} y^{''} (x) + y^{''} (x)

= x^{2} y^{''} (x) + y^{''} (x) + 4 x y^{'} (x) + 2 y

\frac{x + 10}{( x + 2 ) ( x + 20 )}

\frac{( 8 x ^{3} + 13 x )}{( x ^{2} + 2 ) ^{2}}

- \frac{3 u ^{3} ( 4 y ^{3} - 5 )}{2 y ^{2}}

(x^{2} + y^{2}) d x + (x y) d y

lo g_{x^{2}} (y)

What is expand (x^2+1)y''(x)+4xy'(x)+2y ?
The solution to expand (x^2+1)y''(x)+4xy'(x)+2y is x^2y''(x)+y''(x)+4xy'(x)+2y