What is expand 1/((s+1)(s^2+6s+13)) ?

The solution to expand 1/((s+1)(s^2+6s+13)) is 1/(s^3+7s^2+19s+13)

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expand 1/((s+1)(s^2+6s+13))

expand

\frac{1}{( s + 1 ) ( s ^{2} + 6 s + 13 )}

\frac{1}{s ^{3} + 7 s ^{2} + 19 s + 13}

Solution steps

\frac{1}{( s + 1 ) ( s ^{2} + 6 s + 13 )}

Expand

(s + 1) (s^{2} + 6 s + 13) : s^{3} + 7 s^{2} + 19 s + 13

= \frac{1}{s ^{3} + 7 s ^{2} + 19 s + 13}

cos (a t) cos ((a + b) t + c)

\frac{d ^{5}}{d} x^{5} (y = 8 x^{4} - 16 x^{3} - 24 x^{2} + 32 x + 8)

\frac{( 1 - cos ( 2 x - 2 ) )}{( x - 1 ) ^{2}}

x^{2} (x + 1) d x + y^{2} (x - 1)

0.275 x + 0.725 (450 - x = 295)

What is expand 1/((s+1)(s^2+6s+13)) ?
The solution to expand 1/((s+1)(s^2+6s+13)) is 1/(s^3+7s^2+19s+13)