What is expand ((n+1)n(n-1))/6 ?

The solution to expand ((n+1)n(n-1))/6 is (n^3)/6-n/6

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expand ((n+1)n(n-1))/6

expand

\frac{( n + 1 ) n ( n - 1 )}{6}

\frac{n ^{3}}{6} - \frac{n}{6}

Solution steps

\frac{( n + 1 ) n ( n - 1 )}{6}

Expand

(n + 1) n (n - 1) : n^{3} - n

= \frac{n ^{3} - n}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{3} - n}{6} = \frac{n ^{3}}{6} - \frac{n}{6}

= \frac{n ^{3}}{6} - \frac{n}{6}

\frac{4 s}{( L ( 4 s ^{2} + 1 ) )}

1 0^{0.7}

y + 4^{3}

108 + (- 36) - 72

\frac{( 8 x - 3 ) ( x + 2 )}{8 x ^{2} + 25}

What is expand ((n+1)n(n-1))/6 ?
The solution to expand ((n+1)n(n-1))/6 is (n^3)/6-n/6