What is expand l{e^{t+3}u(t-6)} ?

The solution to expand l{e^{t+3}u(t-6)} is le^{t+3}tu-6le^{t+3}u

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expand l{e^{t+3}u(t-6)}

expand

l {e^{t + 3} u (t - 6)}

l e^{t + 3} t u - 6 l e^{t + 3} u

Solution steps

l (e^{t + 3} u (t - 6))

Remove parentheses:

(a) = a

= l e^{t + 3} u (t - 6)

Apply the distributive law:

a (b - c) = ab - a c

a = l e^{t + 3} u, b = t, c = 6

= l e^{t + 3} u t - l e^{t + 3} u \cdot 6

= l e^{t + 3} t u - 6 l e^{t + 3} u

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What is expand l{e^{t+3}u(t-6)} ?
The solution to expand l{e^{t+3}u(t-6)} is le^{t+3}tu-6le^{t+3}u