What is expand (2(x^2+2ln(x+2)-4))/(x^2+2x+1) ?

The solution to expand (2(x^2+2ln(x+2)-4))/(x^2+2x+1) is (2x^2+4ln(x+2)-8)/(x^2+2x+1)

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expand (2(x^2+2ln(x+2)-4))/(x^2+2x+1)

expand

\frac{2 ( x ^{2} + 2 ln ( x + 2 ) - 4 )}{x ^{2} + 2 x + 1}

\frac{2 x ^{2} + 4 ln ( x + 2 ) - 8}{x ^{2} + 2 x + 1}

Solution steps

\frac{2 ( x ^{2} + 2 ln ( x + 2 ) - 4 )}{x ^{2} + 2 x + 1}

Expand

2 (x^{2} + 2 ln (x + 2) - 4) : 2 x^{2} + 4 ln (x + 2) - 8

= \frac{2 x ^{2} + 4 ln ( x + 2 ) - 8}{x ^{2} + 2 x + 1}

((1 - λ) q + λ p) (a \cdot e^{b (1 - λ) q + λ p} + c)

(x - e) (x - 23)

\frac{1}{2} (x e^{x})

\frac{1}{( D ^{2} + a ^{2} ) \cdot sin ( a ) x}

\frac{1}{x ^{\frac{4}{3}} \cdot ( e ^{2 x} + 1 )}

What is expand (2(x^2+2ln(x+2)-4))/(x^2+2x+1) ?
The solution to expand (2(x^2+2ln(x+2)-4))/(x^2+2x+1) is (2x^2+4ln(x+2)-8)/(x^2+2x+1)