What is expand ((x-3)(x-4))/((x+1)^2) ?

The solution to expand ((x-3)(x-4))/((x+1)^2) is (x^2-7x+12)/(x^2+2x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x-3)(x-4))/((x+1)^2)

expand

\frac{( x - 3 ) ( x - 4 )}{( x + 1 ) ^{2}}

\frac{x ^{2} - 7 x + 12}{x ^{2} + 2 x + 1}

Solution steps

\frac{( x - 3 ) ( x - 4 )}{( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{( x - 3 ) ( x - 4 )}{x ^{2} + 2 x + 1}

Expand

(x - 3) (x - 4) : x^{2} - 7 x + 12

= \frac{x ^{2} - 7 x + 12}{x ^{2} + 2 x + 1}

\frac{4 ( s + 2 )}{( s ^{2} + 1 ) ( s - 2 )}

(k + 1) (k +!)!

4 + 22 + \frac{π ( 3 2 + 4 )}{2}

\frac{14 x y}{( x ^{2} + y ^{2} + 1 ) ^{2}}

\frac{2 q - r - p}{( q - r ) ^{2}}

What is expand ((x-3)(x-4))/((x+1)^2) ?
The solution to expand ((x-3)(x-4))/((x+1)^2) is (x^2-7x+12)/(x^2+2x+1)