What is expand 1/((p-1)(p+1)(p+2)) ?

The solution to expand 1/((p-1)(p+1)(p+2)) is 1/(p^3+2p^2-p-2)

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expand 1/((p-1)(p+1)(p+2))

expand

\frac{1}{( p - 1 ) ( p + 1 ) ( p + 2 )}

\frac{1}{p ^{3} + 2 p ^{2} - p - 2}

Solution steps

\frac{1}{( p - 1 ) ( p + 1 ) ( p + 2 )}

Expand

(p - 1) (p + 1) (p + 2) : p^{3} + 2 p^{2} - p - 2

= \frac{1}{p ^{3} + 2 p ^{2} - p - 2}

\frac{d x + u}{( x - v ) ^{2}}

\frac{8 s + 25}{( s + 2 ) ( s ^{3} + 25 s ^{2} - 128 s - 400 )}

\frac{- 9 x + 1}{x ( x - 7 )}

\frac{1}{2} (\frac{6 m - 4}{m})

(1 - x^{2}) y^{''} (x) - 2 x y^{'} (x) + a (a + 1) y

What is expand 1/((p-1)(p+1)(p+2)) ?
The solution to expand 1/((p-1)(p+1)(p+2)) is 1/(p^3+2p^2-p-2)