What is expand (-301F-32)(5/9) ?

The solution to expand (-301F-32)(5/9) is -(1505F)/9-160/9

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expand (-301F-32)(5/9)

expand

(- 301 F^{\circ} - 32) (\frac{5}{9})

- \frac{1505 F ^{\circ}}{9} - \frac{160}{9}

Solution steps

(- 301 F^{\circ} - 32) (\frac{5}{9})

= (\frac{5}{9}) (- 301 F^{\circ} - 32)

Apply the distributive law:

a (b - c) = ab - a c

a = (\frac{5}{9}), b = - 301 F^{\circ}, c = 32

= (\frac{5}{9}) (- 301 F^{\circ}) - (\frac{5}{9}) \cdot 32

Apply minus-plus rules

+ (- a) = - a

= - 301 (\frac{5}{9}) F^{\circ} - 32 (\frac{5}{9})

Simplify

- 301 (\frac{5}{9}) F^{\circ} - 32 (\frac{5}{9}) : - \frac{1505 F ^{\circ}}{9} - \frac{160}{9}

= - \frac{1505 F ^{\circ}}{9} - \frac{160}{9}

(\frac{2 x - 1}{\frac{x}{2}})^{2}

\frac{( - 24 x ^{2} + 12 x - 15 ) ( 4 x - 1 )}{16}

(2 x - 3 y) (\frac{1}{2}, \frac{3}{2})

(x + ln^{2} (x))^{3}

4 x y^{2} - 2 x y + \frac{( 4 x ^{2} y - x ^{2} - 5 ) d y}{d x}

What is expand (-301F-32)(5/9) ?
The solution to expand (-301F-32)(5/9) is -(1505F)/9-160/9