What is expand (2+sin(e^{-bx}+1))^2 ?

The solution to expand (2+sin(e^{-bx}+1))^2 is 4+4sin(e^{-bx}+1)+sin^2(e^{-bx}+1)

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expand (2+sin(e^{-bx}+1))^2

expand

(2 + sin (e^{- b x} + 1))^{2}

4 + 4 sin (e^{- b x} + 1) + sin^{2} (e^{- b x} + 1)

Solution steps

(2 + sin (e^{- b x} + 1))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 2, b = sin (e^{- b x} + 1)

= 2^{2} + 2 \cdot 2 sin (e^{- b x} + 1) + sin^{2} (e^{- b x} + 1)

Simplify

2^{2} + 2 \cdot 2 sin (e^{- b x} + 1) + sin^{2} (e^{- b x} + 1) : 4 + 4 sin (e^{- b x} + 1) + sin^{2} (e^{- b x} + 1)

= 4 + 4 sin (e^{- b x} + 1) + sin^{2} (e^{- b x} + 1)

\frac{ln ( 1 + \frac{x - 1}{x ^{2}} ) ( x + 1 )}{x - 1}

- \frac{5 ( 2 - x ^{\frac{1}{5}} ) ^{4}}{4}

\frac{48}{( 2 s + 1 ) ( 4 s ^{2} + 4 s + 17 )}

sin (θ) (- 7, - 24)

\frac{2 - 5 s}{( s - 6 ) ( s ^{2} + 11 )}

What is expand (2+sin(e^{-bx}+1))^2 ?
The solution to expand (2+sin(e^{-bx}+1))^2 is 4+4sin(e^{-bx}+1)+sin^2(e^{-bx}+1)