What is expand 2pi(pi/6+(sqrt(3))/4) ?

The solution to expand 2pi(pi/6+(sqrt(3))/4) is (pi^2)/3+(sqrt(3)pi)/2

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expand 2pi(pi/6+(sqrt(3))/4)

expand

2 π (\frac{π}{6} + \frac{3}{4})

\frac{π ^{2}}{3} + \frac{3 π}{2}

Solution steps

2 π (\frac{π}{6} + \frac{3}{4})

Apply the distributive law:

a (b + c) = ab + a c

a = 2 π, b = \frac{π}{6}, c = \frac{3}{4}

= 2 π \frac{π}{6} + 2 π \frac{3}{4}

Simplify

2 π \frac{π}{6} + 2 π \frac{3}{4} : \frac{π ^{2}}{3} + \frac{3 π}{2}

= \frac{π ^{2}}{3} + \frac{3 π}{2}

\frac{( 6 x ^{2} - 1 )}{x ^{2} ( x ^{2} + 2 x )}

\frac{2 x ^{3} - x ^{2}}{( 4 x ^{2} + 4 x + 5 ) ^{2}}

(2 y - x) d x

\frac{- 2 ( x + y ) + 3}{( x + y )}

e^{x} \cdot cos (2 x) (e^{x} \cdot sin (2 x) + 2 e^{x} \cdot cos (2 x))

What is expand 2pi(pi/6+(sqrt(3))/4) ?
The solution to expand 2pi(pi/6+(sqrt(3))/4) is (pi^2)/3+(sqrt(3)pi)/2