What is expand (s)(-1/(s+1)-ln(s+1)) ?

The solution to expand (s)(-1/(s+1)-ln(s+1)) is -s/(s+1)-sln(s+1)

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expand (s)(-1/(s+1)-ln(s+1))

expand

(s) (- \frac{1}{s + 1} - ln (s + 1))

- \frac{s}{s + 1} - s ln (s + 1)

Solution steps

(s) (- \frac{1}{s + 1} - ln (s + 1))

Apply the distributive law:

a (b - c) = ab - a c

a = (s), b = - \frac{1}{s + 1}, c = ln (s + 1)

= (s) (- \frac{1}{s + 1}) - (s) ln (s + 1)

Apply minus-plus rules

+ (- a) = - a

= - \frac{1}{s + 1} (s) - (s) ln (s + 1)

Simplify

- \frac{1}{s + 1} (s) - (s) ln (s + 1) : - \frac{s}{s + 1} - s ln (s + 1)

= - \frac{s}{s + 1} - s ln (s + 1)

\frac{x ^{6} - 1}{( x - 4 ) ^{2}}

\frac{( z ^{6} + 1 )}{( z - i )}

\frac{3}{7.5} \cdot 11.5 - x

\frac{( 50 \cdot e ^{- 1.6 s} )}{s ( 11.4 s + 1 )}

\frac{10 s}{( ( s ^{2} + 4 ) ( s ^{2} + 5 s + 6 ) )}

What is expand (s)(-1/(s+1)-ln(s+1)) ?
The solution to expand (s)(-1/(s+1)-ln(s+1)) is -s/(s+1)-sln(s+1)