What is expand (x'-10)(x^2-1) ?

The solution to expand (x'-10)(x^2-1) is x^2x'-x'-10x^2+10

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expand (x'-10)(x^2-1)

expand

(x^{'} - 10) (x^{2} - 1)

x^{2} x' - x' - 10 x^{2} + 10

Solution steps

(x^{'} - 10) (x^{2} - 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = x^{'}, b = - 10, c = x^{2}, d = - 1

= x^{^{'}} x^{2} + x^{^{'}} (- 1) + (- 10) x^{2} + (- 10) (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= x^{2} x^{^{'}} - 1 x^{^{'}} - 10 x^{2} + 10 \cdot 1

Simplify

x^{2} x^{'} - 1 x^{'} - 10 x^{2} + 10 \cdot 1 : x^{2} x^{'} - x^{'} - 10 x^{2} + 10

= x^{2} x^{'} - x^{'} - 10 x^{2} + 10

e^{x (x - 11)}

- (\frac{1}{6} \cdot lo g_{2} (\frac{1}{6}) + \frac{5}{6} \cdot lo g_{2} (\frac{5}{6}))

\frac{( - cos ( y ) ( 2 x sin ( y ) - cos ( x ) ) ) - 1}{x}

\frac{( 7 x + 8 ) ( 6 x + 4 )}{( x ^{2} - 16 ) ^{2}}

\frac{3 x}{( x - 2 ) ( x - 1 )}

What is expand (x'-10)(x^2-1) ?
The solution to expand (x'-10)(x^2-1) is x^2x'-x'-10x^2+10