What is expand (((Rcs+1)/c)I)/(cs) ?

The solution to expand (((Rcs+1)/c)I)/(cs) is (RI)/c+I/(c^2s)

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expand (((Rcs+1)/c)I)/(cs)

expand

\frac{( \frac{R cs + 1}{c} ) I}{cs}

\frac{R I}{c} + \frac{I}{c ^{2} s}

Solution steps

\frac{( \frac{R cs + 1}{c} ) I}{cs}

Remove parentheses:

(a) = a

= \frac{\frac{R cs + 1}{c} I}{cs}

Multiply

\frac{R cs + 1}{c} I : \frac{c R s I + I}{c}

= \frac{\frac{c R s I + I}{c}}{cs}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{c R s I + I}{ccs}

ccs = c^{2} s

= \frac{c R s I + I}{c ^{2} s}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{c R s I + I}{c ^{2} s} = \frac{c R s I}{c ^{2} s} + \frac{I}{c ^{2} s}

= \frac{c R s I}{c ^{2} s} + \frac{I}{c ^{2} s}

Cancel

\frac{c R s I}{c ^{2} s} : \frac{R I}{c}

= \frac{R I}{c} + \frac{I}{c ^{2} s}

(x^{2} + x + 1) e^{x}

\frac{6 + 26 x - x ^{2}}{( 2 x - 1 ) ( x + 2 ) ^{2}}

\frac{1}{( 2 s + 1 ) ( s + 1 )}

π \cdot sin (b) \cdot k \cdot (cos^{2} (a) + 2 \cdot cos (a) + k^{2})

so l v e (x^{3} - 9 x - 7 = 0)

What is expand (((Rcs+1)/c)I)/(cs) ?
The solution to expand (((Rcs+1)/c)I)/(cs) is (RI)/c+I/(c^2s)