What is expand (3(x-2)^2(x+2)^2)/4 ?

The solution to expand (3(x-2)^2(x+2)^2)/4 is (3x^4)/4-6x^2+12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (3(x-2)^2(x+2)^2)/4

expand

\frac{3 ( x - 2 ) ^{2} ( x + 2 ) ^{2}}{4}

\frac{3 x ^{4}}{4} - 6 x^{2} + 12

Solution steps

\frac{3 ( x - 2 ) ^{2} ( x + 2 ) ^{2}}{4}

(x - 2)^{2} = x^{2} - 4 x + 4

= \frac{3 ( x ^{2} - 4 x + 4 ) ( x + 2 ) ^{2}}{4}

(x + 2)^{2} = x^{2} + 4 x + 4

= \frac{3 ( x ^{2} - 4 x + 4 ) ( x ^{2} + 4 x + 4 )}{4}

Expand

3 (x^{2} - 4 x + 4) (x^{2} + 4 x + 4) : 3 x^{4} - 24 x^{2} + 48

= \frac{3 x ^{4} - 24 x ^{2} + 48}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3 x ^{4} - 24 x ^{2} + 48}{4} = \frac{3 x ^{4}}{4} - \frac{24 x ^{2}}{4} + \frac{48}{4}

= \frac{3 x ^{4}}{4} - \frac{24 x ^{2}}{4} + \frac{48}{4}

Divide the numbers:

\frac{24}{4} = 6

= \frac{3 x ^{4}}{4} - 6 x^{2} + \frac{48}{4}

Divide the numbers:

\frac{48}{4} = 12

= \frac{3 x ^{4}}{4} - 6 x^{2} + 12

\frac{( x + h ) ^{2} + 5 ( x + h ) - 7}{h}

\frac{e ^{- s} - e ^{- 2 s} + s ^{2}}{s ^{2} ( s ^{2} - 2 s + 1 )}

\frac{x ^{2}}{( 2 x + 1 ) ( x + 2 ) ^{2}}

\frac{( x - 1 ) ( x - 8 )}{3 x ^{5} - 5 x ^{3} - 7 x - 3}

(- 6, 5) y (- 3, - 3)

What is expand (3(x-2)^2(x+2)^2)/4 ?
The solution to expand (3(x-2)^2(x+2)^2)/4 is (3x^4)/4-6x^2+12