What is (\partial)/(\partial x)((r)(a(cos(x)+1))) ?

The answer to (\partial)/(\partial x)((r)(a(cos(x)+1))) is -arsin(x)

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(\partial)/(\partial x)((r)(a(cos(x)+1)))

\frac{\partial}{\partial x} ((r) (a (cos (x) + 1)))

- a r sin (x)

Solution steps

\frac{\partial}{\partial x} ((r) (a (cos (x) + 1)))

Treat

a, r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r a \frac{\partial}{\partial x} (cos (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= r a (\frac{\partial}{\partial x} (cos (x)) + \frac{\partial}{\partial x} (1))

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

\frac{\partial}{\partial x} (1) = 0

= r a (- sin (x) + 0)

Simplify

= - a r sin (x)

\frac{5 - x}{( 2 x - 1 ) ( x + 1 )}

s - 3 e^{s} s (e^{2 s} - 3 e^{s} + 2)

32 \cdot 0.645

(e^{j t} - e^{- j t})^{2}

(\frac{1 + x}{2})^{5}

What is (\partial)/(\partial x)((r)(a(cos(x)+1))) ?
The answer to (\partial)/(\partial x)((r)(a(cos(x)+1))) is -arsin(x)