What is expand (x+2y-1)(9x+y'(x)+3) ?

The solution to expand (x+2y-1)(9x+y'(x)+3) is 9x^2+xy'(x)-6x+18xy+2yy'(x)+6y-y'(x)-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+2y-1)(9x+y'(x)+3)

expand

(x + 2 y - 1) (9 x + y^{'} (x) + 3)

9 x^{2} + x y' (x) - 6 x + 18 x y + 2 yy' (x) + 6 y - y' (x) - 3

Solution steps

(x + 2 y - 1) (9 x + y^{'} (x) + 3)

Distribute parentheses

= x \cdot 9 x + x y^{^{'}} (x) + x \cdot 3 + 2 y \cdot 9 x + 2 y y^{^{'}} (x) + 2 y \cdot 3 + (- 1) \cdot 9 x + (- 1) y^{^{'}} (x) + (- 1) \cdot 3

Apply minus-plus rules

+ (- a) = - a

= 9 xx + x y^{^{'}} (x) + 3 x + 2 \cdot 9 x y + 2 y y^{^{'}} (x) + 2 \cdot 3 y - 1 \cdot 9 x - 1 y^{^{'}} (x) - 1 \cdot 3

Simplify

9 xx + x y^{'} (x) + 3 x + 2 \cdot 9 x y + 2 y y^{'} (x) + 2 \cdot 3 y - 1 \cdot 9 x - 1 y^{'} (x) - 1 \cdot 3 : 9 x^{2} + x y^{'} (x) - 6 x + 18 x y + 2 y y^{'} (x) + 6 y - y^{'} (x) - 3

= 9 x^{2} + x y^{'} (x) - 6 x + 18 x y + 2 y y^{'} (x) + 6 y - y^{'} (x) - 3

\frac{x + 6}{( x + 7 ) ^{\frac{5}{4}}}

d u l u s (e^{- i x} + i e^{i x})^{2}

12 (cos (2 x))

\frac{d ^{2}}{d x ^{2}} ((y) (5 - 3 x)^{3})

\frac{2 λ ^{2}}{( λ + s ) ( 2 λ + s )}

What is expand (x+2y-1)(9x+y'(x)+3) ?
The solution to expand (x+2y-1)(9x+y'(x)+3) is 9x^2+xy'(x)-6x+18xy+2yy'(x)+6y-y'(x)-3