What is expand p(x,y)A(-3,-4)B(1,2) ?

The solution to expand p(x,y)A(-3,-4)B(1,2) is -3(1*2,)pAB(,xy),-4(1*2,)pAB(,xy)

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expand p(x,y)A(-3,-4)B(1,2)

expand

p (x, y) A (- 3, - 4) B (1, 2)

- 3 (1 \cdot 2,) p A B (, x y), - 4 (1 \cdot 2,) p A B (, x y)

Solution steps

p (x, y) A (- 3, - 4) B (1, 2)

= (- 3, - 4) (1 \cdot 2,) p A B (, x y)

Apply the distributive law:

a (b - c) = ab - a c

a = p (x, y) A B (1, 2), b = - 3,, c = 4

= p (x, y) A B (1, 2) (- 3,) - p (x, y) A B (1, 2) \cdot 4

Apply minus-plus rules

+ (- a) = - a

= - 3 (1 \cdot 2,) p A B (, x y), - 4 (1 \cdot 2,) p A B (, x y)

\frac{d}{d x} ((z) (\frac{y}{x + y} - z))

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\frac{- 2 x ^{3} - 6 x ^{2} a - a}{( x ^{3} - a ) ^{2}}

(x - \frac{1}{e ^{2}})^{2}

\frac{3 x ( a - x ) ^{4}}{4}

What is expand p(x,y)A(-3,-4)B(1,2) ?
The solution to expand p(x,y)A(-3,-4)B(1,2) is -3(1*2,)pAB(,xy),-4(1*2,)pAB(,xy)