What is expand (2s^2-6s+1)/(s(s-3)(s+1)) ?

The solution to expand (2s^2-6s+1)/(s(s-3)(s+1)) is (2s^2-6s+1)/(s^3-2s^2-3s)

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expand (2s^2-6s+1)/(s(s-3)(s+1))

expand

\frac{2 s ^{2} - 6 s + 1}{s ( s - 3 ) ( s + 1 )}

\frac{2 s ^{2} - 6 s + 1}{s ^{3} - 2 s ^{2} - 3 s}

Solution steps

\frac{2 s ^{2} - 6 s + 1}{s ( s - 3 ) ( s + 1 )}

Expand

s (s - 3) (s + 1) : s^{3} - 2 s^{2} - 3 s

= \frac{2 s ^{2} - 6 s + 1}{s ^{3} - 2 s ^{2} - 3 s}

\frac{π ( 18 \cdot 2 ^{\frac{2}{3}} - 14 )}{15}

7 e^{y} (y^{2} - x^{2})

- x e^{x} + x (3 + x)

\frac{d ^{2}}{d h ^{2}} ((v) ((3 h^{2} + 4)^{\frac{3}{2}} - 8))

5 (1 - e^{\frac{10}{t}})

What is expand (2s^2-6s+1)/(s(s-3)(s+1)) ?
The solution to expand (2s^2-6s+1)/(s(s-3)(s+1)) is (2s^2-6s+1)/(s^3-2s^2-3s)