What is expand (3(-t^4+12t^2-12))/(2t^2) ?

The solution to expand (3(-t^4+12t^2-12))/(2t^2) is -(3t^2)/2+18-(18)/(t^2)

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expand (3(-t^4+12t^2-12))/(2t^2)

expand

\frac{3 ( - t ^{4} + 12 t ^{2} - 12 )}{2 t ^{2}}

- \frac{3 t ^{2}}{2} + 18 - \frac{18}{t ^{2}}

Solution steps

\frac{3 ( - t ^{4} + 12 t ^{2} - 12 )}{2 t ^{2}}

Expand

3 (- t^{4} + 12 t^{2} - 12) : - 3 t^{4} + 36 t^{2} - 36

= \frac{- 3 t ^{4} + 36 t ^{2} - 36}{2 t ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 t ^{4} + 36 t ^{2} - 36}{2 t ^{2}} = - \frac{3 t ^{4}}{2 t ^{2}} + \frac{36 t ^{2}}{2 t ^{2}} - \frac{36}{2 t ^{2}}

= - \frac{3 t ^{4}}{2 t ^{2}} + \frac{36 t ^{2}}{2 t ^{2}} - \frac{36}{2 t ^{2}}

Cancel

\frac{3 t ^{4}}{2 t ^{2}} : \frac{3 t ^{2}}{2}

= - \frac{3 t ^{2}}{2} + \frac{36 t ^{2}}{2 t ^{2}} - \frac{36}{2 t ^{2}}

Cancel

\frac{36 t ^{2}}{2 t ^{2}} : 18

= - \frac{3 t ^{2}}{2} + 18 - \frac{36}{2 t ^{2}}

Divide the numbers:

\frac{36}{2} = 18

= - \frac{3 t ^{2}}{2} + 18 - \frac{18}{t ^{2}}

(1.45) (50)

\frac{\frac{2}{3}}{5}

(x^{2} y - 2 x y + 1) + (- 3 x^{2} y + \frac{1}{2})

1 + 500 (1 - (1 - \frac{1}{1000})^{500})

\frac{( 4 x )}{( ( x - a ) ^{(2)} )}

What is expand (3(-t^4+12t^2-12))/(2t^2) ?
The solution to expand (3(-t^4+12t^2-12))/(2t^2) is -(3t^2)/2+18-(18)/(t^2)