What is expand (-2t^5-2t)/((t^4-1)^2(t^2-1)) ?

The solution to expand (-2t^5-2t)/((t^4-1)^2(t^2-1)) is (-2t^5-2t)/(t^{10)-t^8-2t^6+2t^4+t^2-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (-2t^5-2t)/((t^4-1)^2(t^2-1))

expand

\frac{- 2 t ^{5} - 2 t}{( t ^{4} - 1 ) ^{2} ( t ^{2} - 1 )}

\frac{- 2 t ^{5} - 2 t}{t ^{10} - t ^{8} - 2 t ^{6} + 2 t ^{4} + t ^{2} - 1}

Solution steps

\frac{- 2 t ^{5} - 2 t}{( t ^{4} - 1 ) ^{2} ( t ^{2} - 1 )}

(t^{4} - 1)^{2} = t^{8} - 2 t^{4} + 1

= \frac{- 2 t ^{5} - 2 t}{( t ^{8} - 2 t ^{4} + 1 ) ( t ^{2} - 1 )}

Expand

(t^{8} - 2 t^{4} + 1) (t^{2} - 1) : t^{10} - t^{8} - 2 t^{6} + 2 t^{4} + t^{2} - 1

= \frac{- 2 t ^{5} - 2 t}{t ^{10} - t ^{8} - 2 t ^{6} + 2 t ^{4} + t ^{2} - 1}

A (- 1, 0) B (\frac{3}{2}, - \frac{1}{2})

4 sin (2 (π + θ))

d x d (3 x^{2} - 1)

\frac{12}{8}

(x - 9) (x + 14)^{''}

What is expand (-2t^5-2t)/((t^4-1)^2(t^2-1)) ?
The solution to expand (-2t^5-2t)/((t^4-1)^2(t^2-1)) is (-2t^5-2t)/(t^{10)-t^8-2t^6+2t^4+t^2-1}