What are the solutions to the equation x^2+14x-38=0 ?

The solutions to the equation x^2+14x-38=0 are x=-7+sqrt(87),x=-7-sqrt(87)

Find the zeros of x^2+14x-38=0

The zeros of x^2+14x-38=0 are x=-7+sqrt(87),x=-7-sqrt(87)

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x^{2} + 14 x - 38 = 0

x = - 7 + 87, x = - 7 - 87

Decimal Notation

x = 2.32737 \dots, x = - 16.32737 \dots

Solution steps

x^{2} + 14 x - 38 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 38 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 38) = 287

x_{1, 2} = \frac{- 14 \pm 2 87}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 87}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 87}{2 \cdot 1}

x = \frac{- 14 + 2 87}{2 \cdot 1} : - 7 + 87

x = \frac{- 14 - 2 87}{2 \cdot 1} : - 7 - 87

The solutions to the quadratic equation are:

x = - 7 + 87, x = - 7 - 87

9 a^{2} + 46 a + 5 = 0

x^{2} - x < 6

24 3^{\frac{3}{5}}

(\frac{33}{21}) (\frac{2}{3}) (\frac{1}{2})

a = 9000 ((1 + \frac{0.05}{4})^{4 (6)} - 1)

What are the solutions to the equation x^2+14x-38=0 ?
The solutions to the equation x^2+14x-38=0 are x=-7+sqrt(87),x=-7-sqrt(87)
Find the zeros of x^2+14x-38=0
The zeros of x^2+14x-38=0 are x=-7+sqrt(87),x=-7-sqrt(87)