What is expand ((e^2+1)(e+1)(e-1))/(2e^4) ?

The solution to expand ((e^2+1)(e+1)(e-1))/(2e^4) is 1/2-1/(2e^4)

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expand ((e^2+1)(e+1)(e-1))/(2e^4)

expand

\frac{( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{2 e ^{4}}

\frac{1}{2} - \frac{1}{2 e ^{4}}

Solution steps

\frac{( e ^{2} + 1 ) ( e + 1 ) ( e - 1 )}{2 e ^{4}}

Expand

(e^{2} + 1) (e + 1) (e - 1) : e^{4} - 1

= \frac{e ^{4} - 1}{2 e ^{4}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{e ^{4} - 1}{2 e ^{4}} = \frac{e ^{4}}{2 e ^{4}} - \frac{1}{2 e ^{4}}

= \frac{e ^{4}}{2 e ^{4}} - \frac{1}{2 e ^{4}}

Cancel

\frac{e ^{4}}{2 e ^{4}} : \frac{1}{2}

= \frac{1}{2} - \frac{1}{2 e ^{4}}

a (2 - e^{x})

\frac{d}{d x} ((z) (x^{2} y + x y^{2} z))

\frac{2 x ( 4 x ^{3} + x ^{2} + 1 ) + 3}{3 x + 15}

- (\frac{2 1 - ( sin ( t ) ) ( sin ( t ) + 2 )}{3})

e^{3 x^{2} + x} (6 x + 1)

What is expand ((e^2+1)(e+1)(e-1))/(2e^4) ?
The solution to expand ((e^2+1)(e+1)(e-1))/(2e^4) is 1/2-1/(2e^4)