What is expand x(4x^2+5x-3=0) ?

The solution to expand x(4x^2+5x-3=0) is 4x^3+5x^2-3x=0

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expand x(4x^2+5x-3=0)

expand

x (4 x^{2} + 5 x - 3 = 0)

4 x^{3} + 5 x^{2} - 3 x = 0

Solution steps

x (4 x^{2} + 5 x - 3 = 0)

= x (4 x^{2} + 5 x - 3 \cdot 0 =)

Distribute parentheses

= x \cdot 4 x^{2} + x \cdot 5 x + x (- 3 = 0)

Apply minus-plus rules

+ (- a) = - a

4 x^{2} x + 5 xx - 3 x = 0

Expand

4 x^{2} x + 5 xx - 3 x : 4 x^{3} + 5 x^{2} - 3 x

4 x^{3} + 5 x^{2} - 3 x = 0

6 (X - 5 = 12)

(sec^{2} (x))^{2}

\frac{4 i - 3}{( i z + 4 ) \cdot ( z - 3 )}

(y^{2} + 2 y) d x - x^{2} d y

e^{2 t} (e^{t} y + 2 e^{t} y^{'} (t) + e^{t} y^{''} (t))

What is expand x(4x^2+5x-3=0) ?
The solution to expand x(4x^2+5x-3=0) is 4x^3+5x^2-3x=0