What is expand (e^{n+1}-e^n)e^n ?

The solution to expand (e^{n+1}-e^n)e^n is e^{2n+1}-e^{2n}

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expand (e^{n+1}-e^n)e^n

expand

(e^{n + 1} - e^{n}) e^{n}

e^{2 n + 1} - e^{2 n}

Solution steps

(e^{n + 1} - e^{n}) e^{n}

= e^{n} (e^{n + 1} - e^{n})

Apply the distributive law:

a (b - c) = ab - a c

a = e^{n}, b = e^{n + 1}, c = e^{n}

= e^{n} e^{n + 1} - e^{n} e^{n}

Simplify

e^{n} e^{n + 1} - e^{n} e^{n} : e^{2 n + 1} - e^{2 n}

= e^{2 n + 1} - e^{2 n}

- 3 (4 x + 3) + 4 (6 x + 1 = 43)

(x + 1) d y + (y - 1) d x

(e^{- 2 t} - e^{- t})^{2}

\frac{1}{s ^{2} ( s + 5 ) ( s + 1 )}

(- 3, 3) y (- 1, - 5)

What is expand (e^{n+1}-e^n)e^n ?
The solution to expand (e^{n+1}-e^n)e^n is e^{2n+1}-e^{2n}