What is expand ((2x^3-8x^2+9x-2))/((x-2)) ?

The solution to expand ((2x^3-8x^2+9x-2))/((x-2)) is 2x^2-4x+1

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expand ((2x^3-8x^2+9x-2))/((x-2))

expand

\frac{( 2 x ^{3} - 8 x ^{2} + 9 x - 2 )}{( x - 2 )}

2 x^{2} - 4 x + 1

Solution steps

\frac{2 x ^{3} - 8 x ^{2} + 9 x - 2}{x - 2}

Factor

2 x^{3} - 8 x^{2} + 9 x - 2 : (x - 2) (2 x^{2} - 4 x + 1)

= \frac{( x - 2 ) ( 2 x ^{2} - 4 x + 1 )}{x - 2}

Cancel the common factor:

x - 2

= 2 x^{2} - 4 x + 1

x \cdot (e^{\frac{1}{x}} - 1)

- \frac{2 ( 6 x ^{2} + x - 332 )}{( x + 8 ) ( x + 7 ) ( x - 3 )}

e^{3 t} (t + e^{- 2 t})

π + 2 + \frac{1}{2} + \frac{5}{4}

(- 3 e^{x} sin (y) + 2 e^{y} cos (x))^{2}

What is expand ((2x^3-8x^2+9x-2))/((x-2)) ?
The solution to expand ((2x^3-8x^2+9x-2))/((x-2)) is 2x^2-4x+1