What is expand-3+5i-(1+6i,4-2i) ?

The solution to expand-3+5i-(1+6i,4-2i) is -3+5i-1-6i,4+2i

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expand-3+5i-(1+6i,4-2i)

expand

- 3 + 5 i - (1 + 6 i, 4 - 2 i)

- 3 + 5 i - 1 - 6 i, 4 + 2 i

Solution steps

- 3 + 5 i - (1 + 6 i, 4 - 2 i)

= - 3 + 5 i - (1 + 6 \cdot 4 i, - 2 i)

- (1 + 6 i, 4 - 2 i) : - 1 - 6 i, 4 + 2 i

= - 3 + 5 i - 1 - 6 i, 4 + 2 i

\frac{d}{d x} ((t - sin (t)) i) - (1 - cos (t)) j

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e^{x - y} (1 - x)

\frac{( x ^{4} + 1 ) ^{\frac{1}{4}} - ( x ^{2} + 1 ) ^{\frac{1}{2}}}{x ^{2}}

2 sin (\frac{π}{3} (x - 6)) + 2

What is expand-3+5i-(1+6i,4-2i) ?
The solution to expand-3+5i-(1+6i,4-2i) is -3+5i-1-6i,4+2i