What is expand ((9y^4+3x^3-6x^2y+x^2))/((xy^2)) ?

The solution to expand ((9y^4+3x^3-6x^2y+x^2))/((xy^2)) is (9y^2)/x+(3x^2}{y^2}-\frac{6x)/y+x/(y^2)

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expand ((9y^4+3x^3-6x^2y+x^2))/((xy^2))

expand

\frac{( 9 y ^{4} + 3 x ^{3} - 6 x ^{2} y + x ^{2} )}{( x y ^{2} )}

\frac{9 y ^{2}}{x} + \frac{3 x ^{2}}{y ^{2}} - \frac{6 x}{y} + \frac{x}{y ^{2}}

Solution steps

\frac{9 y ^{4} + 3 x ^{3} - 6 x ^{2} y + x ^{2}}{x y ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 y ^{4} + 3 x ^{3} - 6 x ^{2} y + x ^{2}}{x y ^{2}} = \frac{9 y ^{4}}{x y ^{2}} + \frac{3 x ^{3}}{x y ^{2}} - \frac{6 x ^{2} y}{x y ^{2}} + \frac{x ^{2}}{x y ^{2}}

= \frac{9 y ^{4}}{y ^{2} x} + \frac{3 x ^{3}}{y ^{2} x} - \frac{6 y x ^{2}}{y ^{2} x} + \frac{x ^{2}}{y ^{2} x}

\frac{9 y ^{4}}{x y ^{2}} = \frac{9 y ^{2}}{x}

\frac{3 x ^{3}}{x y ^{2}} = \frac{3 x ^{2}}{y ^{2}}

\frac{6 x ^{2} y}{x y ^{2}} = \frac{6 x}{y}

\frac{x ^{2}}{x y ^{2}} = \frac{x}{y ^{2}}

= \frac{9 y ^{2}}{x} + \frac{3 x ^{2}}{y ^{2}} - \frac{6 x}{y} + \frac{x}{y ^{2}}

(2 x + 2)^{7}

\frac{1}{( 1 + 3 x ) ^{2}}

\frac{d}{d x} (\frac{2 y + 4 y ^{2} - x ( 2 x - 1 )}{x})

\frac{( n + 1 ) ( n + 2 )}{6}

\frac{e ^{z \cdot i}}{z ^{2} \cdot ( z - 1 )}

What is expand ((9y^4+3x^3-6x^2y+x^2))/((xy^2)) ?
The solution to expand ((9y^4+3x^3-6x^2y+x^2))/((xy^2)) is (9y^2)/x+(3x^2}{y^2}-\frac{6x)/y+x/(y^2)