What is expand (1+e^{2x})(-2e^{2x}) ?

The solution to expand (1+e^{2x})(-2e^{2x}) is -2e^{2x}-2e^{4x}

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expand (1+e^{2x})(-2e^{2x})

expand

(1 + e^{2 x}) (- 2 e^{2 x})

- 2 e^{2 x} - 2 e^{4 x}

Solution steps

(1 + e^{2 x}) (- 2 e^{2 x})

Apply the distributive law:

a (b + c) = ab + a c

a = (- 2 e^{2 x}), b = 1, c = e^{2 x}

= (- 2 e^{2 x}) \cdot 1 + (- 2 e^{2 x}) e^{2 x}

= 1 \cdot (- 2 e^{2 x}) + e^{2 x} (- 2 e^{2 x})

Simplify

1 \cdot (- 2 e^{2 x}) + e^{2 x} (- 2 e^{2 x}) : - 2 e^{2 x} - 2 e^{4 x}

= - 2 e^{2 x} - 2 e^{4 x}

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What is expand (1+e^{2x})(-2e^{2x}) ?
The solution to expand (1+e^{2x})(-2e^{2x}) is -2e^{2x}-2e^{4x}