What is expand ((1-4^{k+1}))/(-3) ?

The solution to expand ((1-4^{k+1}))/(-3) is -1/3+(4^{k+1})/3

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expand ((1-4^{k+1}))/(-3)

expand

\frac{( 1 - 4 ^{k + 1} )}{- 3}

- \frac{1}{3} + \frac{4 ^{k + 1}}{3}

Solution steps

\frac{1 - 4 ^{k + 1}}{- 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{1 - 4 ^{k + 1}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{1 - 4 ^{k + 1}}{3} = - (\frac{1}{3}) - (- \frac{4 ^{k + 1}}{3})

= - (\frac{1}{3}) - (- \frac{4 ^{k + 1}}{3})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{1}{3} + \frac{4 ^{k + 1}}{3}

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What is expand ((1-4^{k+1}))/(-3) ?
The solution to expand ((1-4^{k+1}))/(-3) is -1/3+(4^{k+1})/3