What is expand x^3*2x+2(2x)^2-x^3*x^2-2(x^2)^2 ?

The solution to expand x^3*2x+2(2x)^2-x^3*x^2-2(x^2)^2 is -x^5+8x^2

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expand x^32x+2(2x)^2-x^3x^2-2(x^2)^2

expand

x^{3} \cdot 2 x + 2 (2 x)^{2} - x^{3} \cdot x^{2} - 2 (x^{2})^{2}

- x^{5} + 8 x^{2}

Solution steps

x^{3} \cdot 2 x + 2 (2 x)^{2} - x^{3} x^{2} - 2 (x^{2})^{2}

x^{3} \cdot 2 x = 2 x^{4}

2 (2 x)^{2} = 2^{3} x^{2}

x^{3} x^{2} = x^{5}

2 (x^{2})^{2} = 2 x^{4}

= 2 x^{4} + 2^{3} x^{2} - x^{5} - 2 x^{4}

Group like terms

= - x^{5} + 2 x^{4} - 2 x^{4} + 2^{3} x^{2}

Add similar elements:

2 x^{4} - 2 x^{4} = 0

= - x^{5} + 2^{3} x^{2}

2^{3} = 8

= - x^{5} + 8 x^{2}

arcsin (\frac{1}{1.33})

\frac{1}{4 a ( a - b )}

10 (\frac{1}{2} x + \frac{2}{5} y = 4)

\frac{8 ( 2 p + q )}{p - q}

\frac{d}{d t} ((x) (2 t e^{- 5 t} - \frac{t + 13}{t ^{2} + t - 6}))

What is expand x^3*2x+2(2x)^2-x^3*x^2-2(x^2)^2 ?
The solution to expand x^3*2x+2(2x)^2-x^3*x^2-2(x^2)^2 is -x^5+8x^2