What is expand ((x-1)(2x-5))/((x+3)) ?

The solution to expand ((x-1)(2x-5))/((x+3)) is (2x^2-7x+5)/(x+3)

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expand ((x-1)(2x-5))/((x+3))

expand

\frac{( x - 1 ) ( 2 x - 5 )}{( x + 3 )}

\frac{2 x ^{2} - 7 x + 5}{x + 3}

Solution steps

\frac{( x - 1 ) ( 2 x - 5 )}{x + 3}

Expand

(x - 1) (2 x - 5) : 2 x^{2} - 7 x + 5

= \frac{2 x ^{2} - 7 x + 5}{x + 3}

\frac{( 3 s ^{2} + 4 )}{s ( s ^{2} + 4 )}

121 \cdot 18 - 121 \cdot 8

\frac{1}{( 4 x - 1 ) ^{5}}

(1 - t^{2}) d t

\frac{( 2 + x ) ^{6}}{( x ^{4} ( 2 x + 1 ) ( x + 4 ) )}

What is expand ((x-1)(2x-5))/((x+3)) ?
The solution to expand ((x-1)(2x-5))/((x+3)) is (2x^2-7x+5)/(x+3)