What is expand sin(2t)U(t-(3pi)/2) ?

The solution to expand sin(2t)U(t-(3pi)/2) is tUsin(2t)-(3piUsin(2t))/2

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expand sin(2t)U(t-(3pi)/2)

expand

sin (2 t) U (t - \frac{3 π}{2})

t U sin (2 t) - \frac{3 π U sin ( 2 t )}{2}

Solution steps

sin (2 t) U (t - \frac{3 π}{2})

= U sin (2 t) (t - \frac{3 π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = sin (2 t) U, b = t, c = \frac{3 π}{2}

= sin (2 t) U t - sin (2 t) U \frac{3 π}{2}

= t U sin (2 t) - \frac{3 π}{2} U sin (2 t)

Simplify

t U sin (2 t) - \frac{3 π}{2} U sin (2 t) : t U sin (2 t) - \frac{3 π U sin ( 2 t )}{2}

= t U sin (2 t) - \frac{3 π U sin ( 2 t )}{2}

\frac{1}{x ^{2} ( a x + 1 )}

(e^{2 x} + ln (x))^{2}

4 e (3 e - 5) - 2 e (e - 7)

\frac{10}{9 \cdot ( 3 \cdot t + e ^{- 3 \cdot t} - 1 )}

3 - 2 ((- a c h) + a e hb e g + b c g)

What is expand sin(2t)U(t-(3pi)/2) ?
The solution to expand sin(2t)U(t-(3pi)/2) is tUsin(2t)-(3piUsin(2t))/2