What is the d/(dt)((s(t))(4t^2-6t-5)) ?

The d/(dt)((s(t))(4t^2-6t-5)) is s(12t^2-12t-5)

What is the first d/(dt)((s(t))(4t^2-6t-5)) ?

The first d/(dt)((s(t))(4t^2-6t-5)) is s(12t^2-12t-5)

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\frac{d}{d t} ((s (t)) (4 t^{2} - 6 t - 5))

s (12 t^{2} - 12 t - 5)

Solution steps

\frac{d}{d t} ((s (t)) (4 t^{2} - 6 t - 5))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= s \frac{d}{d t} (t (4 t^{2} - 6 t - 5))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = 4 t^{2} - 6 t - 5

= s (\frac{d t}{d t} (4 t^{2} - 6 t - 5) + \frac{d}{d t} (4 t^{2} - 6 t - 5) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (4 t^{2} - 6 t - 5) = 8 t - 6

= s (1 \cdot (4 t^{2} - 6 t - 5) + (8 t - 6) t)

Simplify

s (1 \cdot (4 t^{2} - 6 t - 5) + (8 t - 6) t) : s (12 t^{2} - 12 t - 5)

= s (12 t^{2} - 12 t - 5)

(3 y + 15)^{\circ} (3 y + 15) + (2 y + 5)

\frac{12 x ^{2} + 18}{x ( x ^{2} + 4 )}

e^{(x + 2)^{3}}

(x - y) \cdot e^{x - y}

\frac{s ^{3} + 25 s ^{2} + 289}{( s ^{3} + 25 s ^{2} + 3.4 s + 306 ) s}

What is the d/(dt)((s(t))(4t^2-6t-5)) ?
The d/(dt)((s(t))(4t^2-6t-5)) is s(12t^2-12t-5)
What is the first d/(dt)((s(t))(4t^2-6t-5)) ?
The first d/(dt)((s(t))(4t^2-6t-5)) is s(12t^2-12t-5)