What are the solutions to the equation 3z^2+2z-1=0 ?

The solutions to the equation 3z^2+2z-1=0 are z= 1/3 ,z=-1

Find the zeros of 3z^2+2z-1=0

The zeros of 3z^2+2z-1=0 are z= 1/3 ,z=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 z^{2} + 2 z - 1 = 0

z = \frac{1}{3}, z = - 1

Decimal Notation

z = 0.33333 \dots, z = - 1

Solution steps

3 z^{2} + 2 z - 1 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 1) = 4

z_{1, 2} = \frac{- 2 \pm 4}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 2 + 4}{2 \cdot 3}, z_{2} = \frac{- 2 - 4}{2 \cdot 3}

z = \frac{- 2 + 4}{2 \cdot 3} : \frac{1}{3}

z = \frac{- 2 - 4}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

z = \frac{1}{3}, z = - 1

- 7 + \frac{1}{3}

x^{2} + x - 2

x^{2} - 9 x + 10

1 \leq 3 x - 5 \leq 10

k^{2} - 7 k + 6

What are the solutions to the equation 3z^2+2z-1=0 ?
The solutions to the equation 3z^2+2z-1=0 are z= 1/3 ,z=-1
Find the zeros of 3z^2+2z-1=0
The zeros of 3z^2+2z-1=0 are z= 1/3 ,z=-1