What is expand (x-5)(3x+4)-(2x-4)'(3x+7)' ?

The solution to expand (x-5)(3x+4)-(2x-4)'(3x+7)' is 3x^2-11x-20-(2x-4)'(3x+7)'

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expand (x-5)(3x+4)-(2x-4)'(3x+7)'

expand

(x - 5) (3 x + 4) - (2 x - 4)^{'} (3 x + 7)^{'}

3 x^{2} - 11 x - 20 - (2 x - 4)' (3 x + 7)'

Solution steps

(x - 5) (3 x + 4) - (2 x - 4)^{'} (3 x + 7)^{'}

Expand

(x - 5) (3 x + 4) : 3 x^{2} - 11 x - 20

= 3 x^{2} - 11 x - 20 - (2 x - 4)^{'} (3 x + 7)^{'}

\frac{d}{d x} ((z) (- e^{z} + x^{2} + y^{2} + z^{2}))

- \frac{16 x}{( x ^{2} + 4 ) ( - x ^{2} + 4 )}

\frac{5 ( 10 a + 11 b )}{9}

\frac{( x ^{2} + 1 )}{( x - 1 ) ^{2}}

\frac{d}{d x} ((z (x, y)) (2 x^{2} y^{3} + x^{2} y))

What is expand (x-5)(3x+4)-(2x-4)'(3x+7)' ?
The solution to expand (x-5)(3x+4)-(2x-4)'(3x+7)' is 3x^2-11x-20-(2x-4)'(3x+7)'