What is expand ((3z-1)z)/(3(z-1)(z+2)) ?

The solution to expand ((3z-1)z)/(3(z-1)(z+2)) is (3z^2-z)/(3z^2+3z-6)

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expand ((3z-1)z)/(3(z-1)(z+2))

expand

\frac{( 3 z - 1 ) z}{3 ( z - 1 ) ( z + 2 )}

\frac{3 z ^{2} - z}{3 z ^{2} + 3 z - 6}

Solution steps

\frac{( 3 z - 1 ) z}{3 ( z - 1 ) ( z + 2 )}

Expand

3 (z - 1) (z + 2) : 3 z^{2} + 3 z - 6

= \frac{z ( 3 z - 1 )}{3 z ^{2} + 3 z - 6}

Expand

(3 z - 1) z : 3 z^{2} - z

= \frac{3 z ^{2} - z}{3 z ^{2} + 3 z - 6}

- 1 (x - y = 10)

\frac{( x ( 7 - 7 x ) ^{2} )}{2}

(8 x^{2} + 6 x - 5) d x

(2 (x + h) + 4)^{\frac{1}{2}} - (2 x + 4)^{\frac{1}{2}}

cos (y (5 x + 2 y^{2}))

What is expand ((3z-1)z)/(3(z-1)(z+2)) ?
The solution to expand ((3z-1)z)/(3(z-1)(z+2)) is (3z^2-z)/(3z^2+3z-6)