What is expand (2x-y=2,)(x+y+3=0) ?

The solution to expand (2x-y=2,)(x+y+3=0) is 2x^2+2xy+6x=0

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expand (2x-y=2,)(x+y+3=0)

expand

(2 x - y = 2,) (x + y + 3 = 0)

2 x^{2} + 2 x y + 6 x = 0

Solution steps

(2 x - y = 2,) (x + y + 3 = 0)

= (2 x - 2 =, y) (x + y + 3 \cdot 0 =)

Distribute parentheses

2 xx + 2 x y + 2 x \cdot 3 = 0 + (- y = 2,) x + (- y = 2,) y + (- y = 2,) \cdot 3 = 0

Apply minus-plus rules

+ (- a) = - a

2 xx + 2 x y + 2 \cdot 3 x = 0 - y = 2, x - y = 2, y - y = 2, 3 = 0

Expand

2 xx + 2 x y + 2 \cdot 3 x : 2 x^{2} + 2 x y + 6 x

2 x^{2} + 2 x y + 6 x = 0

(23 - 32) (5 + 43)

\frac{s ^{2} + s + 1}{s ^{3} ( s + 1 )}

\frac{1}{( x ( x ^{2} + 1 ) )}

- 4.16 z (z - 1) (z - e^{- T})

2 (5.5 - y - y = 2)

What is expand (2x-y=2,)(x+y+3=0) ?
The solution to expand (2x-y=2,)(x+y+3=0) is 2x^2+2xy+6x=0