What are the solutions to the equation 27m^2-48=0 ?

The solutions to the equation 27m^2-48=0 are m= 4/3 ,m=-4/3

Find the zeros of 27m^2-48=0

The zeros of 27m^2-48=0 are m= 4/3 ,m=-4/3

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27 m^{2} - 48 = 0

m = \frac{4}{3}, m = - \frac{4}{3}

Decimal Notation

m = 1.33333 \dots, m = - 1.33333 \dots

Solution steps

27 m^{2} - 48 = 0

Move

48

to the right side

27 m^{2} = 48

Divide both sides by

27

m^{2} = \frac{16}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{16}{9}, m = - \frac{16}{9}

\frac{16}{9} = \frac{4}{3}

- \frac{16}{9} = - \frac{4}{3}

m = \frac{4}{3}, m = - \frac{4}{3}

∣ x - 1 ∣ = 2 x + 1

0.654 = 60.9 (x)

2 y^{2} + 3 = - 7 y

2 \geq \frac{y}{5} - 1

5 x^{2} = \frac{4}{3} x

What are the solutions to the equation 27m^2-48=0 ?
The solutions to the equation 27m^2-48=0 are m= 4/3 ,m=-4/3
Find the zeros of 27m^2-48=0
The zeros of 27m^2-48=0 are m= 4/3 ,m=-4/3