What is expand ((2+sqrt(2))sqrt(2-\sqrt{2)})/2 ?

The solution to expand ((2+sqrt(2))sqrt(2-\sqrt{2)})/2 is sqrt(2-\sqrt{2)}+(sqrt(4-2\sqrt{2)})/2

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expand ((2+sqrt(2))sqrt(2-\sqrt{2)})/2

expand

\frac{( 2 + 2 ) 2 - 2}{2}

2 - 2 + \frac{4 - 2 2}{2}

Decimal

1.30656 \dots

Solution steps

\frac{( 2 + 2 ) 2 - 2}{2}

Expand

(2 + 2) 2 - 2 : 2 2 - 2 + 4 - 22

= \frac{2 2 - 2 + 4 - 2 2}{2}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 2 - 2 + 4 - 2 2}{2} = \frac{2 2 - 2}{2} + \frac{4 - 2 2}{2}

= \frac{2 2 - 2}{2} + \frac{4 - 2 2}{2}

Divide the numbers:

\frac{2}{2} = 1

= 2 - 2 + \frac{4 - 2 2}{2}

\frac{sin ^{2} ( x ) tan ^{4} ( x )}{( x ^{2} + 1 ) ^{2}}

\frac{u ^{3} ( u - 4 )}{4}

x^{2} d v - (vx - x) d x

(10 x + 6 + x + 24 = 180) (10 + 6)

a (- 1, 2, 5) b (- 3, 4, - 2)

What is expand ((2+sqrt(2))sqrt(2-\sqrt{2)})/2 ?
The solution to expand ((2+sqrt(2))sqrt(2-\sqrt{2)})/2 is sqrt(2-\sqrt{2)}+(sqrt(4-2\sqrt{2)})/2