What is (\partial ^2)/(\partial u\partial x)((x)(-2x+u(x))) ?

The answer to (\partial ^2)/(\partial u\partial x)((x)(-2x+u(x))) is 2x

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(\partial ^2)/(\partial u\partial x)((x)(-2x+u(x)))

\frac{\partial ^{2}}{\partial u \partial x} ((x) (- 2 x + u (x)))

2 x

Solution steps

\frac{\partial ^{2}}{\partial u \partial x} ((x) (- 2 x + u (x)))

\frac{\partial}{\partial u} (x (- 2 x + ux)) = x^{2}

= \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 2 x

\frac{( A s ) + B}{( s ^{2} + 1 ) ^{2}} + \frac{( C s ) + D}{s ^{2} + 1}

\frac{4 ( x + 1 )}{2 x + 1}

q (200 - 200 q - b q)^{2}

(100 - 2 π x)^{2}

(cos (x^{2} - 1))^{2}

What is (\partial ^2)/(\partial u\partial x)((x)(-2x+u(x))) ?
The answer to (\partial ^2)/(\partial u\partial x)((x)(-2x+u(x))) is 2x