What is expand (9x+27)(9y-9)^' ?

The solution to expand (9x+27)(9y-9)^' is 9x(9y-9)^'+27(9y-9)^'

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expand (9x+27)(9y-9)^'

expand

(9 x + 27) (9 y - 9)^{^{'}}

9 x (9 y - 9)^{'} + 27 (9 y - 9)^{'}

Solution steps

(9 x + 27) (9 y - 9)^{^{'}}

Apply the distributive law:

a (b + c) = ab + a c

a = (9 y - 9)^{^{'}}, b = 9 x, c = 27

= (9 y - 9)^{^{^{'}}} \cdot 9 x + (9 y - 9)^{^{^{'}}} \cdot 27

= 9 x (9 y - 9)^{^{^{'}}} + 27 (9 y - 9)^{^{^{'}}}

\frac{1}{( x - h ) ^{3}}

(- 3 x^{2} + 12 x - 8) - (x^{2} - 4 x + 4) d x

8^{(2 v^{2} - v)^{7}}

(x - 1) (e^{T} x - 1)

- \frac{4 ( x ^{2} + 4 x + 2 )}{9 x ^{\frac{5}{3}} ( x + 2 ) ^{\frac{8}{3}}}

What is expand (9x+27)(9y-9)^' ?
The solution to expand (9x+27)(9y-9)^' is 9x(9y-9)^'+27(9y-9)^'