What is the d/(dt)((θ(t))(4.1t+12.6t^2)) ?

The d/(dt)((θ(t))(4.1t+12.6t^2)) is θ(37.8t^2+8.2t)

What is the first d/(dt)((θ(t))(4.1t+12.6t^2)) ?

The first d/(dt)((θ(t))(4.1t+12.6t^2)) is θ(37.8t^2+8.2t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((θ (t)) (4.1 t + 12.6 t^{2}))

θ (37.8 t^{2} + 8.2 t)

Solution steps

\frac{d}{d t} ((θ (t)) (4.1 t + 12.6 t^{2}))

Treat

θ

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= θ \frac{d}{d t} (t (4.1 t + 12.6 t^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = 4.1 t + 12.6 t^{2}

= θ (\frac{d t}{d t} (4.1 t + 12.6 t^{2}) + \frac{d}{d t} (4.1 t + 12.6 t^{2}) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (4.1 t + 12.6 t^{2}) = 4.1 + 25.2 t

= θ (1 \cdot (4.1 t + 12.6 t^{2}) + (4.1 + 25.2 t) t)

Simplify

θ (1 \cdot (4.1 t + 12.6 t^{2}) + (4.1 + 25.2 t) t) : θ (37.8 t^{2} + 8.2 t)

= θ (37.8 t^{2} + 8.2 t)

(X + X Y^{^{'}}) [Y + XZ (Y + XZ) + Y^{^{'}}]

A (1, 1, 3) B (2, - 1, 5) C (- 3, 3, 1)

\frac{x ^{2} - 2 x - 1}{( x ^{2} + 1 ) ^{2}}

\frac{1}{( s + 2 ) ( s ^{2} + 3 )}

(x - 1) e

What is the d/(dt)((θ(t))(4.1t+12.6t^2)) ?
The d/(dt)((θ(t))(4.1t+12.6t^2)) is θ(37.8t^2+8.2t)
What is the first d/(dt)((θ(t))(4.1t+12.6t^2)) ?
The first d/(dt)((θ(t))(4.1t+12.6t^2)) is θ(37.8t^2+8.2t)