What is expand (5-t)(\H((t-3)-\H(t-7))) ?

The solution to expand (5-t)(\H((t-3)-\H(t-7))) is 5\H(t-3-\H(t-7))-t\H(t-3-\H(t-7))

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expand (5-t)(\H((t-3)-\H(t-7)))

expand

(5 - t) (H ((t - 3) - H (t - 7)))

5 H (t - 3 - H (t - 7)) - t H (t - 3 - H (t - 7))

Solution steps

(5 - t) (H ((t - 3) - H (t - 7)))

= (H ((t - 3) - H (t - 7))) (5 - t)

Apply the distributive law:

a (b - c) = ab - a c

a = (H ((t - 3) - H (t - 7))), b = 5, c = t

= (H ((t - 3) - H (t - 7))) \cdot 5 - (H ((t - 3) - H (t - 7))) t

= 5 (H ((t - 3) - H (t - 7))) - t (H ((t - 3) - H (t - 7)))

Remove parentheses:

(a) = a

= 5 H (t - 3 - H (t - 7)) - t H (t - 3 - H (t - 7))

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What is expand (5-t)(\H((t-3)-\H(t-7))) ?
The solution to expand (5-t)(\H((t-3)-\H(t-7))) is 5\H(t-3-\H(t-7))-t\H(t-3-\H(t-7))