What is expand-sin(t)(θ(t-pi/2)) ?

The solution to expand-sin(t)(θ(t-pi/2)) is -tθsin(t)+(piθsin(t))/2

Popular >

expand-sin(t)(θ(t-pi/2))

expand

- sin (t) (θ (t - \frac{π}{2}))

- tθ sin (t) + \frac{π θ sin ( t )}{2}

Solution steps

- sin (t) (θ (t - \frac{π}{2}))

Remove parentheses:

(a) = a

= - sin (t) θ (t - \frac{π}{2})

= - θ sin (t) (t - \frac{π}{2})

Apply the distributive law:

a (b - c) = ab - a c

a = - sin (t) θ, b = t, c = \frac{π}{2}

= - sin (t) θt - (- sin (t) θ) \frac{π}{2}

Apply minus-plus rules

- (- a) = a

= - tθ sin (t) + \frac{π}{2} θ sin (t)

\frac{π}{2} θ sin (t) = \frac{π θ sin ( t )}{2}

= - tθ sin (t) + \frac{π θ sin ( t )}{2}

1 + \frac{1.7 ( s + 2 ) K}{s ^{2} + 2 s + 1.81}

\frac{( x - a ) x + 2 a ^{2}}{( x + a ) x - 2 a ^{2}}

(0) (9 i) (1 - i)

\frac{5 n ( 3 ^{n} + 1 )}{n + 3 ^{n + 1} + 1}

\frac{3 \cdot ( - x ^{2} + 3 )}{x ^{4}}

What is expand-sin(t)(θ(t-pi/2)) ?
The solution to expand-sin(t)(θ(t-pi/2)) is -tθsin(t)+(piθsin(t))/2