What is expand (3y^{1/3}= 1/2 x^2+C) 1/3 ?

The solution to expand (3y^{1/3}= 1/2 x^2+C) 1/3 is y^{1/3}=(x^2)/2+C/3

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expand (3y^{1/3}= 1/2 x^2+C) 1/3

expand

(3 y^{\frac{1}{3}} = \frac{1}{2} x^{2} + C) \frac{1}{3}

y^{\frac{1}{3}} = \frac{x ^{2}}{2} + \frac{C}{3}

Solution steps

(3 y^{\frac{1}{3}} = \frac{1}{2} x^{2} + C) \frac{1}{3}

= \frac{1}{3} (3 \cdot \frac{1}{2} = x^{2} y^{\frac{1}{3}} + C)

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{3}, b = 3 y^{\frac{1}{3}} = \frac{1}{2} x^{2}, c = C

\frac{1}{3} \cdot 3 y^{\frac{1}{3}} = \frac{1}{2} x^{2} + \frac{1}{3} C

3 \cdot \frac{1}{3} y^{\frac{1}{3}} = \frac{1}{2} x^{2} + \frac{1}{3} C

Simplify

3 \cdot \frac{1}{3} y^{\frac{1}{3}} = \frac{1}{2} x^{2} + \frac{1}{3} C : y^{\frac{1}{3}} = \frac{x ^{2}}{2} + \frac{C}{3}

y^{\frac{1}{3}} = \frac{x ^{2}}{2} + \frac{C}{3}

\frac{4 ( r + 1 ) ^{3}}{3}

(a x^{2} y^{4} e^{x^{3} y^{4}} + \frac{3}{x ^{2} + 1}) d x

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\frac{( 2 x ^{2} + x ) ^{2}}{4}

\frac{s}{( s + 2 ) ^{2} ( s ^{2} + 25 )}

What is expand (3y^{1/3}= 1/2 x^2+C) 1/3 ?
The solution to expand (3y^{1/3}= 1/2 x^2+C) 1/3 is y^{1/3}=(x^2)/2+C/3