What is expand (3(3x-5)^2)/((2x+3)^2) ?

The solution to expand (3(3x-5)^2)/((2x+3)^2) is (27x^2-90x+75)/(4x^2+12x+9)

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expand (3(3x-5)^2)/((2x+3)^2)

expand

\frac{3 ( 3 x - 5 ) ^{2}}{( 2 x + 3 ) ^{2}}

\frac{27 x ^{2} - 90 x + 75}{4 x ^{2} + 12 x + 9}

Solution steps

\frac{3 ( 3 x - 5 ) ^{2}}{( 2 x + 3 ) ^{2}}

(2 x + 3)^{2} = 4 x^{2} + 12 x + 9

= \frac{3 ( 3 x - 5 ) ^{2}}{4 x ^{2} + 12 x + 9}

(3 x - 5)^{2} = 9 x^{2} - 30 x + 25

= \frac{3 ( 9 x ^{2} - 30 x + 25 )}{4 x ^{2} + 12 x + 9}

Expand

3 (9 x^{2} - 30 x + 25) : 27 x^{2} - 90 x + 75

= \frac{27 x ^{2} - 90 x + 75}{4 x ^{2} + 12 x + 9}

30 (x + \frac{12}{π} sin (\frac{π x}{12}))

\frac{( - a x ^{2} - 2 ) - a x ^{2} + 1}{3 a ^{2}}

(π - x) d x

\frac{5}{( x ^{2} + x + 1 ) ( x - 2 )}

\frac{7 x - 5}{( x - 2 ) ( x + 1 )}

What is expand (3(3x-5)^2)/((2x+3)^2) ?
The solution to expand (3(3x-5)^2)/((2x+3)^2) is (27x^2-90x+75)/(4x^2+12x+9)