What is the derivative of (m(x^2-1)) ?

The derivative of (m(x^2-1)) is 2mx

What is the first derivative of (m(x^2-1)) ?

The first derivative of (m(x^2-1)) is 2mx

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\frac{d}{d x} ((m) (x^{2} - 1))

2 m x

Solution steps

\frac{d}{d x} ((m) (x^{2} - 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= m \frac{d}{d x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= m (\frac{d}{d x} (x^{2}) - \frac{d}{d x} (1))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= m (2 x - 0)

Simplify

= 2 m x

10 + (x^{2} + 6 x - 1)

- \frac{2 s ^{2} + 4 s + 3}{( s + 1 ) s ^{2}}

x y d x + (7 x^{2} + 9 x + 2 x^{3} y^{5} - 2) d y

26 x^{4} 5

\frac{( \frac{1}{3} ) ( ( - \frac{1}{3} ) ^{10} - 1 )}{- \frac{1}{3} - 1}

What is the derivative of (m(x^2-1)) ?
The derivative of (m(x^2-1)) is 2mx
What is the first derivative of (m(x^2-1)) ?
The first derivative of (m(x^2-1)) is 2mx