What is expand in((x^2-4)/(x^2+1)) ?

The solution to expand in((x^2-4)/(x^2+1)) is (inx^2-4in)/(x^2+1)

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expand in((x^2-4)/(x^2+1))

expand

in (\frac{x ^{2} - 4}{x ^{2} + 1})

\frac{in x ^{2} - 4 in}{x ^{2} + 1}

Solution steps

in (\frac{x ^{2} - 4}{x ^{2} + 1})

Remove parentheses:

(a) = a

= in \frac{x ^{2} - 4}{x ^{2} + 1}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{2} - 4 ) in}{x ^{2} + 1}

Expand

(x^{2} - 4) in : in x^{2} - 4 in

= \frac{in x ^{2} - 4 in}{x ^{2} + 1}

\frac{d}{d y} ((x) (x^{2} + sin (5 x)))

e l i p se (16 x^{2} - 4 x y + 16 y^{2} - 112 x - 136 y = 704)

\frac{1}{5} e^{x} (e^{x} - 1)

\frac{4 x y + 2 y ^{2} - 4 x ^{2}}{( x - y ) ( x + y )}

\frac{a + b}{2 ( a - b )}

What is expand in((x^2-4)/(x^2+1)) ?
The solution to expand in((x^2-4)/(x^2+1)) is (inx^2-4in)/(x^2+1)