What is expand (2(3pi-4)a^3)/9 ?

The solution to expand (2(3pi-4)a^3)/9 is (2pia^3)/3-(8a^3)/9

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expand (2(3pi-4)a^3)/9

expand

\frac{2 ( 3 π - 4 ) a ^{3}}{9}

\frac{2 π a ^{3}}{3} - \frac{8 a ^{3}}{9}

Solution steps

\frac{2 ( 3 π - 4 ) a ^{3}}{9}

Expand

2 (3 π - 4) a^{3} : 6 π a^{3} - 8 a^{3}

= \frac{6 π a ^{3} - 8 a ^{3}}{9}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 π a ^{3} - 8 a ^{3}}{9} = \frac{6 π a ^{3}}{9} - \frac{8 a ^{3}}{9}

= \frac{6 π a ^{3}}{9} - \frac{8 a ^{3}}{9}

Cancel

\frac{6 π a ^{3}}{9} : \frac{2 π a ^{3}}{3}

= \frac{2 π a ^{3}}{3} - \frac{8 a ^{3}}{9}

π (6 - \frac{ln ( 2 )}{16})

\frac{5 z ^{2} + 2 z + 3}{( z + 2 ) ( z - 1 )}

\frac{x ^{3} - 1}{x ( x + 1 ) ^{3}}

\frac{( t + 1 ) ( t - 1 )}{t ^{2} - 4}

\frac{2 x ^{3} - 3 x ^{2} + 5 x}{( x ^{2} + 2 ) ( x - 3 )}

What is expand (2(3pi-4)a^3)/9 ?
The solution to expand (2(3pi-4)a^3)/9 is (2pia^3)/3-(8a^3)/9